# How to print ith node in Linked List in Python

# Define a Node class

class Node:

def __init__(self, value, next=None):

self.value = value

self.next = next

# Define a LinkedList class

class LinkedList:

def __init__(self, head=None):

self.head = head

def get_node(self, index):

# Set the current node to the head

current = self.head

# Iterate through the list until the desired node is found

for i in range(index):

if current:

current = current.next

else:

raise IndexError('List index out of range')

# Return the value of the node

return current.value

# Test the LinkedList class

node1 = Node(1)

node2 = Node(2)

node3 = Node(3)

node4 = Node(4)

node1.next = node2

node2.next = node3

node3.next = node4

linked_list = LinkedList(node1)

print(linked_list.get_node(0)) # Output: 1

print(linked_list.get_node(2)) # Output: 3

This approach works by iterating through the list using a loop and returning the value of the ` i`-th node when it is found. If the index is out of range, an IndexError is raised

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